C Program to Find Roots of Quadratic Equation

Here you will get C program to find roots of quadratic equation ax²+bx+c=0

Program:

#include<stdio.h>

#include<math.h>

int main()

{

    float root1,root2,a,b,c,d,imaginaryPart,realPart;

    printf("Quadratic Equation is ax^2+bx+c=0");

    printf("\nEnter values of a,b and c:");

    scanf("%f%f%f",&a,&b,&c);

    

    d=(b*b)-(4*a*c);

    if(d>0)

    {

        printf("\nTwo real and distinct roots");

        root1=(-b+sqrt(d))/(2*a);

        root2=(-b-sqrt(d))/(2*a);

        printf("\nRoots are %f and %f",root1,root2);

    }

    else

        if(d==0)

        {

            printf("\nTwo real and equal roots");

            root1=root2=-b/(2*a);

            printf("\nRoots are %f and %f",root1,root2);

        }

        else{

            printf("\nRoots are complex and imaginary");

            realPart = -b/(2*a);

            imaginaryPart = sqrt(-d)/(2*a);

            printf("\nRoots are %.2f+%.2fi and %.2f-%.2fi", realPart, imaginaryPart, realPart, imaginaryPart);

        }

    return 0;            

}

Output
Quadratic Equation is ax^2+bx+c=0
Enter values of a,b and c:1
1
1
Roots are complex and imaginary
Roots are -0.50+0.87i and -0.50-0.87i